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bonufazy [111]
3 years ago
5

12a-4(5a-1) = 2(3a +6)-4a

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

The answet to the following question is a = -5/4.

You distribute and then combine similar terms.

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gulaghasi [49]

Answer:

4

Step-by-step explanation:

AO = OC

3x - 4 = 8

x = 4

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tangare [24]

Answer: 177.5


Step-by-step explanation:so to find to area u need to multiply 16 times 16,which gives u a area of 256. Now to find to Area of circle u need to do 5*5 becuse 5 is the radius,and that is 25. 25*3.14=78.5. So we need to subtract 256-78.5=177.5.


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3 years ago
Evaluate 12x - 1 when x = 4
Slav-nsk [51]
12(4)-1

48-1

47 is the answer
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3 years ago
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20 POINTS AND BRAINLIEST<br> QUESTION ABOUT GRAPHS, PLEASE ANSWER
Rudik [331]

Answer:

The answer is straight

Step-by-step explanation:

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8 0
3 years ago
F(x) = x^2+x-2/x^2-3x-4
Andrej [43]

i. Domain and Range

The given function is

f(x)=\frac{x^2+x-2}{x^2-3x-4}


The domain of this function is,

x^2-3x-4\ne 0

(x-4)(x+1)\ne 0

x\ne4,xne -1


The range refers to the y-values for which x is defined. x  is defined for all values of y.

The range is all real numbers. See graph

ii. x-and-y-intercept

For x- intercept intercept we put f(x)=0

This implies that;

\frac{x^2+x-2}{x^2-3x-4}=0


This will give us

x^2+x-2=0

\Rightarrow x^2+x-2=0


\Rightarrow x^2+2x--x-2=0

\Rightarrow x(x+2)-1(x+2)=0

\Rightarrow (x+2)(x-1)=0


\Rightarrow (x+2)=0,(x-1)=0

\Rightarrow x=-2,x=1

The x-intercepts are (-2,0),(1,0)


For y-intercept, we put

x=0 to obtain;

f(0)=\frac{0^2+0-2}{0^2-3(0)-4}

f(0)=\frac{1}{2}

The y-intercept is

(0,\frac{1}{2})

iii. Horizontal asyptote

Since degree of the numerator and the denominator are the same, there is a horizontal asymptote

To find the horizontal asymptote.


We divide the leading coefficient of the numerator by the leading  coefficient of the denominator.


The horizontal asymptote is y=\frac{1}{1}=1

iv. Vertical asymptote

To find the vertical asymptote, we equate the denominator to zero to get;

x^2-3x-4=0


This implies that;

x^2+x-4x-4=0

Split the middle term

x(x+1)-4(x+1)=0

Factor

(x+1)(x-4)=0

Factor further

(x+1)=0,(x-4)=0

x=-1,x=4


The vertical asymptotes are x=-1,x=4




8 0
3 years ago
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