<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer:
Step-by-step explanation:
Ok, so first substitute x for 4 in
"g(x) = 5x + 1", and x for 3 in
"k(x) = 2/x + 2x". Now you got:
g(4) = 5(4) + 1
k(3) = 2/(3) + 2(3)
Now you can solve each individually.
g(4) = 5 × 4 = 20
20 + 1 = 21
g(4) = 21
k(3) = 2 × 3 = 6
6 + 2/3 = 6 2/3
k(3) = 6 2/3
g(4) + k(3) = 21 + 6 2/3 = <u>27 2/3</u>
Hope this helps :)
Answer: Total number of pairs =872
Step-by-step explanation:
Since we have given that
Number of pairs of skates during the month of April =218
Number of pairs of skates during the month of May =3 × 218=654
As we know that total means altogether in which we perform the additive operation.
Total pairs of skates the skating rent during April and May = 218+654=872
∴ Total number of pairs =872
Answer:y=negative 1 over 3x +2
Step-by-step explanation:
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3
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Explanation:
There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative.
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A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative
sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative
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If we allow m to be negative, then the final result would be either |m^3| or |m|^3.
The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.
Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2
