You're trying to find constants

such that

. Equivalently, you're looking for the least-square solution to the following matrix equation.

To solve

, multiply both sides by the transpose of

, which introduces an invertible square matrix on the LHS.

Computing this, you'd find that

which means the first choice is correct.
Answer:
the answer is 34
Step-by-step explanation:
first we put the equation together (4x^2+4x+1)by(2x^2+x-2)
so we multiply the formula together so we (4x^2+4x+1) (2x^2+-2) and that's how you get 34
3 Rd side would be
13sq=12sq+xsq
Xsq=169-144
X=5
Cot theta = adj side/opp side= 5/12