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3 years ago

Which two sets of angles are corresponding angles?

Mathematics

2 answers:

pychu [463]3 years ago

8 0

I believe angles R and Q are corresponding, as well as angles P and S. The angles correspond with one another because the rings match up with one another. R and Q both have one ring, and P and S both have two rings.

Bond [772]3 years ago

8 0

Answer:

(angle q, angle r) and (angle p, angle s) are the sets of the corresponding angles.

Step-by-step explanation:

Two triangles have been given in the figure attached.

To identify the corresponding angles we will understand the which are the corresponding sides.

Side with length 2 in small triangle is half of the side with length 4 units.

Similarly, sides with length 3 in small triangle is half of the side of length 6 units

And side with length 2.5 in small triangle is half of the the side of 5 units length.

Therefore, corresponding sides are (2 units, 4 units), (2.5 units, 5 units) and (3 units, 6 units).

Now angles opposite to the corresponding sides will be corresponding.

(angle q, angle r) and (angle p, angle s) are the sets of the corresponding angles.

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3 years ago

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3 years ago

Help I can’t get the answer

djverab [1.8K]

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2 years ago

What is the final answer?

MakcuM [25]

<h3>Answer: 42</h3>

Explanation:

We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c

where,

a = -0.9
b = 76
c = -250

The vertex (h,k) is when the profit is maxed out.

h = -b/(2a)

h = -76/(2(-0.9))

h = 42.222 approximately

Let's plug in x values around x = 42

Try x = 41

y = -0.9x^2 + 76x - 250

y = -0.9(41)^2 + 76(41) - 250

y = 1353.10

Now try x = 42

y = -0.9x^2 + 76x - 250

y = -0.9(42)^2 + 76(42) - 250

y = 1354.4

Now try x = 43

y = -0.9x^2 + 76x - 250

y = -0.9(43)^2 + 76(43) - 250

y = 1353.9

We see that the largest profit happens when x = 42.

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2 years ago

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Answer:

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$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable who represents the file sizeof music. We know the following info:

$\mu =2.3,\sigma =3.25$

We select a sample of n=50 nails. That represent the sample size.

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

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3 years ago