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3 years ago

(-6)-13 subtracting integers

Mathematics

2 answers:

inessss [21]3 years ago

5 0

-19 hope this helps this is the answer plz thank me afte

myrzilka [38]3 years ago

4 0

-19
Hope this helps!! c:

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Bob walked 2,640 yards to the bus stop. Then, the bus traveled 3 miles to the library. How far did Bob travel in total to the li

trapecia [35]

15,840 feet hope that helps

3 0

3 years ago

Please check my homework on Negative Indices!

rusak2 [61]

Our first expression is $(2p^{-3} q^{8} )^{4}$ . Upon distributing the exponent 4 on all the terms, we get:

$(2p^{-3} q^{8} )^{4}=2^{4}(p^{-3})^{4}(q^{8})^{4}=16p^{-12}q^{32}=\frac{16q^{32}}{p^{12}}$

Therefore, your answer is correct for this part. :)

Second expression is $(2m^{-4}n^{5})^{-2}$ . Upon distributing the exponent -2 on all the terms, we get:

$(2m^{-4}n^{5})^{-2}=2^{-2}(m^{-4})^{-2}(n^{5})^{-2}=2^{-2}m^{8}n^{-10}=\frac{m^{8}}{4n^{10}}$

Your second answer is correct too.

Our third expression is $2(5g^{-4}h^{-6})^{2}$ . Upon distributing the exponent 2 on all the terms, we get:

$2(5g^{-4}h^{-6})^{2}=2(5^{2})(g^{-4})^{2}(h^{-6})^{2}=2(25)g^{-8}h^{-12}=\frac{50}{g^{8}h^{12}}$

This one is not correct. Your answer would have been correct, if the exponent were -2 instead of 2 in this part.

Our forth and last expression is $4(2c^{-3}d^{6})^{-5}$ . Upon distributing the exponent -5 on all the terms inside the parenthesis, we get:

$4(2c^{-3}d^{6})^{-5}=4(2^{-5})(c^{-3})^{-5}(d^{6})^{-5}=\frac{4}{2^{5}}(c^{15})(d^{-30})=\frac{4c^{15}}{32d^{30}}=\frac{c^{15}}{8d^{30}}$

Therefore, your answer for this part is also correct.

Looking at your work, I don't think you made a mistake in number 3 also, probably mis-typed the question while writing here :)

3 0

4 years ago

SOMEONE HELP ASAP PLEASE!

Tanzania [10]

I hope this helps you

5 0

3 years ago

ILL MARK BRAINLIEST SOMEONE HELP PLSPLSOLSPLAPLSPSLSLJFJ ASAPAPAPPAP

Sav [38]

Answer:

You would have to look at the explanation since there are multiple

Step-by-step explanation:

-7x + 1 would have to be greater than or equal to 15.

-7(2) + 1 = 15 so you would mark a filled in dot at 2 and point an arrow going to the right.

6x + 3 must be greater than or equal to -21.

6(-4) + 3 would equal -21 so you would mark a filled in dot at negative 4 with an arrow going to the right.

3 0

3 years ago

Photo attached please help

svetlana [45]

Wouldn’t it be C ? I think it’s c

7 0

3 years ago

Read 2 more answers