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mojhsa [17]
3 years ago
14

Perform the indicated operation.(4r/r+3) - (5/r)

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

Answer:

4r² - 5r - 15 / r(r+3)

Step-by-step explanation:

To solve this problem, we will proceed the following way, writing down the common multiple of the denominators.

\frac{4r}{r+3} -\frac{5}{r} =\frac{4r(r)-5(r+3)}{r(r+3)} =\frac{4r^{2}-5r-15 }{r(r+3)}

Thus, the answer is 4r² - 5r - 15 / r(r+3)

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2 years ago
Two equations are given below: a − 3b = 9 a = b − 3 What is the solution to the set of equations in the form (a, b)? (−9, −6) (−
Anna [14]

To solve this equation you can plug in these numbers into the equations, so for example you can that the equation a-3b=9 and the points are (-9,-6). you would then insert the numbers so you would have the equation (-9)-3(-6)=9. simplify -9+18=9 and there you have it, the answer is (-9,-6)

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3 years ago
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Leona [35]

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Step-by-step explanation:

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3 years ago
Tanya says .53 is greater than .7 because 53 is greater than 7 Can you explain her mistake?
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4 0
3 years ago
Read 2 more answers
What is the volume of a hemisphere with a radius of 2.3m round to the nearest tenth of a cubic meter
kodGreya [7K]

Answer: 25.5 m^{3}

Step-by-step explanation:

If the volume of a sphere is

V=\frac{4}{3} \pi r^{3}

Where r=2.3 m is the radius

The volume of a hemisphere is half the volume of the total sphere:

V_{hemisphere}=\frac{V}{2}=\frac{\frac{4}{3} \pi r^{3}}{2}

V_{hemisphere}=\frac{2}{3} \pi r^{3}

Solving this equation:

V_{hemisphere}=\frac{2}{3} \pi (2.3 m)^{3}

Finally:

V_{hemisphere}=25.48m^{3} \approx 25.5 m^{3}

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