<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
To find it directly
A = 2 pi r h
A is proportional to rh
factor 2
A is multiplied by 2 * 2 = 4
factor 3
3 * 3 =9
factor 5
5 * 5 = 25
factor 10
10 * 10 = 100
(b) the increase in A by factor x is x^2
c(20)^2 = 400
Answer:
32
Step-by-step explanation:
32 × 1 = 32
8 × 4 = 32
Therefore, the LCM is 32
