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3 years ago

Which option will be most cost effective?why?

Mathematics

1 answer:

Olin [163]3 years ago

6 0

Option 2 would cost more, because $42 for every 6 person, and there are 72 in total, so let's do the math. take the 72 and divide it by 6 to know how many pair of $42 you gonna spend. 72/6 is 12, and 12x$42 is $504. and the first option is $500 flat. so option 1 is the best option, cause at any time one of the guess might want to invite a random person, so you'd have to pay for every 6 person a guess on your list bring. while paying $500 flat wouldn't affect your paying rates.

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dem82 [27]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Construct an argument that shows that the set of rational numbers is closed under division. That is, if x and y are

masha68 [24]

Answer:

$\frac{x}{y}$ can also be expressed as a ratio of two integers.

Step-by-step explanation:

Assume x and y are rational number, then x and y can be written as:

$x=\frac{a}{b}$ , where a and b are integers and b≠0

$y=\frac{c}{d}$ , where c and d are integers and d≠0

Then,

$\frac{x}{y}$ = $\frac{\frac{a}{b} }{\frac{c}{d} }$

= $\frac{a*d}{b*c}$

Since the set of integers are closed under multiplication, a*d is also an integer. Similarly b*c is also an integer.

$\frac{x}{y}$ can be expressed as a proportion of two integers, provided that y≠0. From this we can conclude that $\frac{x}{y}$ is a rational number, which concludes that the set of rational numbers are closed under division.

3 0

3 years ago

Draw a motel of 13/5

Marrrta [24]

I really hope this helps ya! Not much but I think it's correct

6 0

3 years ago

An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 290 engines

Nana76 [90]

Answer:

z(s) = - 2,15 We accept H₀

Step-by-step explanation:

Assume Normal Distribution.

Sample size n = 290

Sample mean μ = 7,6

Sample standard deviation s = 0,8

Level of significance 0,02 ( CI = 98 % )

population mean μ₀ = 7,5

α = 0,02 the valve could fail under and above the spec value ( 7,6 ) therefore we must develop a two-tail test

α/2 = 0,01

Hypothesis Test

Null hypothesis H₀ μ = μ₀

Alternative Hypothesis Hₐ μ ≠ μ₀

for α = 0,01 z(c) = - 2,3

To calculate z(s)

z(s) = ( μ - μ₀ ) / s/√n

z(s) = ( 7,5 - 7,6 ) /0,8/√290

z(s) = - 0,1 * 17 /0,8

z(s) = - 1,7 / 0,8

z(s) = - 2,15

Comparing z(s) and z(c)

- 2, 15 < - 2,3

|z(s)| < | z(c)|

Then z(s) is in the acceptance region. We don´t have evidence to reject H₀

5 0

3 years ago

A jar contains black marbles and green marbles. Sixty percent of the marbles in the jar are green. A number generator simulates

Natali5045456 [20]

Answer:

The number generator is not fair. In most of the experiments, considerably less than 60% of the selected marbles are green.

Step-by-step explanation:

Run a significant number of times, a fair distribution should be a bell curve centered on the 6 for 60%

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2 years ago