Question

Please help me on this

Answer 1

For this case, we have that by definition, the HF segment is given by:

$Sin (45) = \frac {\sqrt {8}} {HF}\\HF = \frac {\sqrt {8}} {sin (45)}\\HF = \frac {\sqrt {8}} {0.7071}\\HF = 4$

Now we find the angle FHE, which by definition will be given:

$tg (FHE) = \frac {3} {HF}\\tg (FHE) = \frac {3} {4}\\tg (FHE) = 0.75\\FHE = tg ^ {- 1} (0.75) = 36.86989765$

Incidentally, the cosine of the FHE angle will be:

$cos (36.86989765) = 0.6755$

Answer:

0.6755

Answer 2

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