For the first one it’s D.3
Answer:
(B) Segments MA and MB
Step-by-step explanation:
The tangent to the circle at a point is perpendicular to the radius of the circle drawn to the point of tangency.
Tangent at a point is unique.
Since there can be no two tangents at a point on circle, the options (b) and (c) are ruled out.
Now, if OA is perpendicular to MA, MA is the tangent else if OA is perpendicular to PA, PA is the tangent. Same is the case with point B.
Tangents from the same external point has same length.
MA = MB since they are the radii of the same circle with center M.
Hence, MA and MB meet all the requirements of the tangents.
Answer:
A) (4,1) C) (12,3) D) (20,5)
Step-by-step explanation:
Required
Which has a constant of proportionality of 1/4
To solve this, we make use of:
Where k is the constant of proportionality.
Solve for x
<u>Testing the given options</u>
A) (4,1)
B) (8,12)
C) (12,3)
D) (20,5)
E) (12,6)
The answer is: H0: μ = 76.4 versus Ha: μ > 76.4, where μ = the true mean height of all trucks.
Answer:
$6
Step-by-step explanation:
This is for one pencil to each student. Since each box is $3, and she has 25 students, you would figure out how many students are left out with one box, and since you only have one left, you only need one more box. That would mean two boxes, so $3x2= $6
