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marin [14]
2 years ago
8

If BE= 2x-3 and AC=3X+1 FIND AC

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
6 0
In a rectangle, the diagonals are equal. You need to set the two equal to each other. The line BE would be doubled to equal AC. Then solve:
2(2x-3)=3x+1
4x-6=3x+1
x=7
Now that you have x, you can find AC. Just plug it in.
3(7)+1
21+1
22
There you have it! AC=22
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Quadrilateral ABDE is a rectangle. DE = 4 in. and BD = 6 in. If the rectangle is rotated about a line through CF, cylinder Y is
postnew [5]

Answer:

1 in. is the answer.

Step-by-step explanation:

Solution: A Rectangle ABDE in which DE=4 inches and BD= 6 inches

 There are two kinds of rotations

1. one along the Breadth, side having length 6 inches,i.e rotated along line GH,  Cylinder Z is created.

Radius of cylinder Z=6/2= 3 inches

2. Second along the Length, Side having length 4 inches,i.e rotated about a line CF, cylinder Y is created.

Radius of cylinder Y= 4/2= 2 inches

Difference in Radii= Radius of cylinder Z  -  Radius of cylinder Y

                              =  3 - 2= 1 inches

Diagram shown below of both the cases:

7 0
3 years ago
Read 2 more answers
5 (10k + 1) + 2 (2 + 8k)
Eddi Din [679]

Answer:

66k+9

Step-by-step explanation:

Simplify: 50k+5+4+16k

Combine like-terms: 66k+9

Hope this helps

6 0
3 years ago
Read 2 more answers
Each morning Rin rides 1.5 miles to school and then rides home in the afternoon. Later in the evening, she rides to the park and
Anarel [89]

Answer:

option b is the answer

your welcome by the wat

3 0
2 years ago
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Solve for x: 2x/5=12/8
Anika [276]

Answer:

x = 3\frac{3}{4}

Step-by-step explanation:

First, you have to leave 2x by itself on the left side of the equation:

2x = 60/8

Then divide,

x = 15/4

Simplified fraction: x = 3\frac{3}{4}

5 0
3 years ago
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I need help ASAP on Tangent Circles!!
loris [4]
I will solve one for you to get you a idea so next u can solve all
To know whether line is tangent toa circle or not we should know that that line is a tangent line of a circle if it intersects circle at single point.
and this will always be perpendicular at radius
so in problem
1)

diameter is given 7.5 
and u can see they make a right triangle ABC if that is perpendicular so segment  AB is tangent to a circle.
Lets see by applying <span>Pythagorean Theorem
</span>this is method we can say that this is in fact a right triangle

a^2=b^2=c^2
a,b are shorter side c is longer side
(7.5)^2+(8)^2=(17)^2
 56.25+64=289
120.25=289
both are not equal so they are not forming right triangle so segment AB is not a tangent line.
5 0
3 years ago
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