we can always find the x-intercept by simply settting y = 0, and solving for "x".
and we can always find the y-intercept by simply setting x = 0 and solving for "y".
![\bf x-4y=-16\implies \stackrel{x=0}{0-4y=-16}\implies y=\cfrac{-16}{-4}\implies y=4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (0,4)~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20x-4y%3D-16%5Cimplies%20%5Cstackrel%7Bx%3D0%7D%7B0-4y%3D-16%7D%5Cimplies%20y%3D%5Ccfrac%7B-16%7D%7B-4%7D%5Cimplies%20y%3D4%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%280%2C4%29~%5Chfill%20)
For this case we have the following line:
x = 4
The first thing you should know is that the slope of the line is given by:
m = (y2-y1) / (x2-x1)
In this case:
x2 = x1
Thus,
The slope is:
m = (y2-y1) / (0)
m = infinity
Answer:
The slope of the line is:
m = infinity
Answer:
c=3
Step-by-step explanation:
8=-5(-1)^2-10(-1)+c
8=5+c
c=3
I believe the answer is 4.