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2 years ago

The expression

Mathematics

1 answer:

mafiozo [28]2 years ago

4 0

Answer:

(2) x2+1+4/x+2

Step-by-step explanation:

I hope i am right sorry if i am wrong.

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3 years ago

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vazorg [7]

Answer: ( 0, 2 )

Step-by-step explanation:

You have to put coordinates of each graph on these equations y = -x + 2 and y = (1/2)x + 2. If putting coordinates satisfies both equations, then that coordinate will be the solution.

For example, let's put (0, 2) to equations.

y = -x + 2

2 = -0 + 2

2 = 2, true

y = (1/2)x + 2

2 = (1/2) × 0 + 2

2 = 2, true

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2 years ago

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Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

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3 years ago

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2 years ago

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