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Mashutka [201]
3 years ago
12

The length of a rectangle is 5 less than twice the width. If the perimeter of the rectangle is 146 centimeters, find the dimensi

ons of the rectangle.
Mathematics
1 answer:
artcher [175]3 years ago
8 0
Length of rectangle = 5 less than 2x width
Perimeter = 146 cm

<u>Equations we will use...</u>
w = width
(2w - 5) = length (l)
perimeter (p) = 2(l + w)

<u>Substitute equation for </u><u>length</u><u> into equation for </u><u>perimeter</u>
p = 2(l + w)
146 = 2((2w - 5) + w)     
[use distributive prop.]
146 = 4w - 10 + 2w        [combine like terms]
146 = 6w -10                  
[solve for w]
156 = 6w
w = 26 cm

<u>Now substitute width back into the </u><u>equation</u><u> for length...</u>
l = 2w - 5
l = 2(26) - 5
l = 47

Double check to make sure values added up to 146 cm
w + w + l + l = 146
26 + 26 + 47 + 47 = 146
146 = 146

Therefore, the width is 26 cm and the length is 47 cm.


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3 0
2 years ago
13 = m/4 + 7 can you show work too
lukranit [14]

The correct value of this equation is <u>m = </u><u>24</u>

<h3>Resolution method</h3>

This equation contains a fractional term. We note that the denominator of this equation is the <u>term 4</u>. Therefore, we will multiply the sides by <u>4</u>:

13 = m/4 + 7

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Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

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