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Darina [25.2K]
2 years ago
12

How much interest is earned on a $5,000 loan at 10% interest for 3 years?

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer:

$1500

.................

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HELPPPPPPPP!!!!!!!!!!
Novosadov [1.4K]

Step-by-step explanation:

98 = 188t - 16t^2

-16t^2 + 188t = 98

-16t^2 + 188t - 98 = 0

8t^2 - 94t + 49 = 0

Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions

t = [(47 - root 1817) / 8]≈ 0.55

and

t = [(47 + root 1817) / 8] ≈ 11.20

8 0
3 years ago
What is the solution to the equation-3(h+5)+2 = 4(h+6)- 9?<br> h= 4<br> h= -2<br> h = 2<br> h = 4
ruslelena [56]
Expanding
-3h-15+2=4h+24-9
-3h-4h=24-9-2+15
-7h=28
h=4
8 0
2 years ago
The Neolithic Revolution
Amanda [17]

The Neolithic Revolution allowed people to live in permanent settlements.

<u>Explanation:</u>

The Neolithic Revolution is the phase of transition in which many of the human cultures in the world shifted their lifestyle to permanent settlement and agriculture from hunting and gathering.

This era is also named as First Agricultural Revolution or Neolithic Demographic Transition. The agricultural practices led the cultures to develop the knowledge of domestication of animals and they began to observe and experiment with the plants (to learn or know how they grow and develop).

Neolithic period is named as revolution because this period changed the way of life of most of the communities. This first occurred in so-called "Fertile Crescent" or Mesopotamia (modern Iraq).

6 0
3 years ago
Read 2 more answers
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
2 years ago
Using 3 5 and 8 once to equal 104
igomit [66]
Trial and error tried 8 x 6 =48 i used 10 x 5 to get closer to 100 10 x 5= 50 50+ 48= 98 all I need is 6 which is 2 x 3 8 x 6 = 48 5 x 10= 50 3 x 2 = 6 Total = 104 Hope this helps
7 0
3 years ago
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