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Jobisdone [24]
3 years ago
7

What does the number of electrons on the outer energy level of an atom tell you

Biology
1 answer:
adell [148]3 years ago
5 0
Well, first off it tells you the number of valence electrons (because that’s what those are valence electrons) it also tells you how that atom is going to bond with other atoms (whether it will tend to loose or gain electrons when in chemical bonds). It also can show how reactive an element is (if it has eight or in some cases two then it won’t react because that outer shell is full)...basically it tells you the chemical properties of that atom
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3 years ago
We get wood from trees. Tree - wood - ________. What word BEST fills in the blank and describes what makes up wood? A) atoms B)
NeX [460]
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Answer:

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Explanation:

3 0
3 years ago
Buffers are weak acids or bases that can react with strong acids or bases to Please select the best answer from the choices prov
stealth61 [152]

Answer:

A buffer is simply a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid. Buffers work by reacting with any added acid or base to control the pH.

Explanation:

5 0
3 years ago
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

6 0
3 years ago
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