The product of a number, x, and six is four more than the product of the number and three-eighths. Which answer represents this
2 answers:
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<u>Before </u><u>answering </u><u>the </u><u>given </u><u>question</u><u>, </u><u>you </u><u>should </u><u>know </u><u>the </u><u>difference </u><u>between </u><u>polygon </u><u>and </u><u>regular </u><u>polygon</u><u>. </u>
- Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
- Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .
<u>There </u><u>are </u><u>different </u><u>types </u><u>of </u><u>polygon </u><u>based </u><u>on </u><u>the </u><u>sides </u><u>:</u><u>-</u>
- A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.
I have thought to make a 4 side polygon that is quadrilateral.
<u>Steps </u><u>of </u><u>construction </u><u>:</u><u>-</u><u> </u>
- Step - 1 :- Draw a 5 cm line AB horizontally
- Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
- Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
- Step - 4 :- Now, join the line AD
- Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.
<u>Result </u><u>:</u><u>-</u><u> </u> All the angles are equal that is 90° each.
<u>Conclusion </u><u>:</u><u>-</u><u> </u> The above figure is square as it is having equal sides and angles.
<h3><u>Now</u><u>, </u><u>we </u><u>have </u><u>to </u><u>find </u><u>the </u><u>sum </u><u>of </u><u>the</u><u> </u><u>angles</u><u> </u><u>of </u><u>the </u><u>polygon </u><u>:</u><u>-</u></h3><u>Here</u><u>, </u><u> </u>
- All angles are equal in measure 90°
<u>Therefore</u><u>, </u>
The sum of the angles of the given polygon
Hence, The sum of the angles of the above polygon is 360° .
Answer:
see below
Step-by-step explanation:
Find the magnitude (-1)^2 + (sqrt3)^2 = m^2 m = 2
find the angle arctan (sqrt3/-1) = 120 degrees
the cube root would then be
(cos 40 + isin 40)