9 are left take 17 and subtract 8
Answer:
(4x² + 3)(16
- 12x² + 9)
Step-by-step explanation:
A sum of cubes factors as
a³ + b³ = (a + b)(a² - ab + b²)
64
= (4x²)³ ⇒ a = 4x²
27 = 3³ ⇒ b = 3
Hence
64 + 27
(4x² + 3)((4x²)² - (4x² × 3) + 3²)
= (4x² + 3)(16 - 12x² + 9)
Forget about the negative sign. First you have to find a least common denominator. This would be 63. Since we had to multiply 9 by 7 to get 63 we have to multiply the numerator (4) by 7. This gives us a new fraction of 36/63. Since we ha e to multiply 21 by 3 to get 63 we have to multiply 19 by 3. This gives us 57. So now we have 36/63 and 57/63. Then we add the negative sign back in making 57/63 -57/63. Now we add them together. Because one has a negative sign and one is positive the number has to be closer to zero. So the answer is -21/63.
10-47
11-42.16
12-48.65
13-2.4
14-7.9
15-8.15
Hope it helps :)
Answer:
Step-by-step explanation:
because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number so that there will be at least one variable with the same number but with opposite signs.
it does not matter which variable you choose.
lets use y because 2 and 3 are smaller then 2 and 5.
so lets multiply the first equation by 2 in order to get y equal to 6.
2(2x)+2(3y)=(2)6
(do not forget to multiply what the equation is equal to also)
4x+6y=12
now for the second equation we need y to equal negative 6
-3(5x)+-3(2y)=-3(4)
-15x-6y=-12
now lets put the 2 new equations next to each other and see what we can cancel out
4x+6y=12
-15x-6y=-12
-11x=0
x=0
now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.
2(0)+3y=6
3y=6
y=2
so your answer is x=0, y=2
