Answer:
1,-3,-5
Step-by-step explanation:
Given:
f(x)=x^3+7x^2+7x-15
Finding all the possible rational zeros of f(x)
p= ±1,±3,±5,±15 (factors of coefficient of last term)
q=±1(factors of coefficient of leading term)
p/q=±1,±3,±5,±15
Now finding the rational zeros using rational root theorem
f(p/q)
f(1)=1+7+7-15
=0
f(-1)= -1 +7-7-15
= -16
f(3)=27+7(9)+21-15
=96
f(-3)= (-3)^3+7(-3)^2+7(-3)-15
= 0
f(5)=5^3+7(5)^2+7(5)-15
=320
f(-5)=(-5)^3+7(-5)^2+7(-5)-15
=0
f(15)=(15)^3+7(15)^2+7(15)-15
=5040
f(-15)=(-15)^3+7(-15)^2+7(-15)-15
=-1920
Hence the rational roots are 1,-3,-5 !
If

is the amount of salt in the tank at time

, then the rate at which this amount changes over time is given by the ODE


We're told that the tank initially starts with no salt in the water, so

.
Multiply both sides by an integrating factor,

:




Since

, we have

so that the amount of salt in the tank over time is given by

After 10 minutes, the amount of salt in the tank is
This is a chemistry problem btw. But, either way, the formula for density is mass per unit of volume. To solve for volume, bring the D over to get M/D = V
(327g)/(1.05g/ml) is the equation. Grams cancel and you’re stuck with 311.428571mL. That isn’t your answer tho, because that isn’t the right amount of sig figs. We have two figs at the least so the right answer would be 311.42 or 311.43mL. We want it in scientific notation, so move the decimal place between 3 and 1. That’s two spots to the left, so the power would be 2. C is your right answer
My chem professor told me to round to even instead of rounding up all the time. Either way, the hundreds place is always a percent error of plus or minus 0.01
Answer: Hello mate!
You have one $20 bill, two $10 bills, three $5 bills and four $1 bills in a bag.
This adds to a total of 10 bills in the bag, and you want to know the expected value if you took one at random.
The expected value is defined as ∑pₙxₙ
where pₙ is the probability for each event (in this case is the number of bills of a given price divided the number of bills in the bag) and xₙ is the value of the bill.
Then we can write the expected value as:
E = (1/10)*$20 + (2/10)*$10 + (3/10)*$5 + (4/10)*$1 = (1/10)( 20$ + 2*$10 + 3*$5 + 4*$1) = (1/10)*($59) = $5.90
The expected value is $5.90.