C is the correct answer because in order to factor it completely, you need to factor by grouping it
-4
= 0
Solution
Here we have to find the factors.
![x^{2} - 4y^{2} = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20-%204y%5E%7B2%7D%20%3D%200)
Here we can write 4y^2 as (2y)^2
![x^{2} - (2y)^{2} = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20-%20%282y%29%5E%7B2%7D%20%20%3D%200)
Now we have to use the formula, a^2 - b^2 = (a + b)(a - b)
Here a = x and b = 2y
Therefore, we get
(x + 2y)(x -2y)
Hence, the answer isC. (x + 2y)(x -2y)
Yes it’s true and that’s why i think so lol
Answer:
h(11) = -20 + 11(11)
h(11) = -20 + 121
h(11) = 101
Step-by-step explanation:
replace t by 11
do multiplication
add them together