X^2-4y^2=0
A.(x+4y)(x-y)
B. (x-4y)(x+y)
C. (x+2y)(x-2y)
D. (x-2y)(x-2y)
1 answer:
-4 = 0
Solution
Here we have to find the factors.
Here we can write 4y^2 as (2y)^2
Now we have to use the formula, a^2 - b^2 = (a + b)(a - b)
Here a = x and b = 2y
Therefore, we get
(x + 2y)(x -2y)
Hence, the answer isC. (x + 2y)(x -2y)
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