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3 years ago

How do I solve this?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

4 0

The rate is constant

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Find the distance between the points (4,-2), (4,-5)

kiruha [24]

$\text{Given that,}\\\\(x_1,y_1) = (4,-2)~~ \text{and}~~ (x_2 ,y_2) = (4,-5)\\\\\text{Distance} = \sqrt{(x_2-x_1)^2 + (y_2 -y_1)^2}\\\\~~~~~~~~~~~~=\sqrt{(4-4)^2 + (-5+2)^2}\\\\~~~~~~~~~~~~=\sqrt{0^2+(-3)^2}\\\\~~~~~~~~~~~~=\sqrt{0+9}\\\\~~~~~~~~~~~~=\sqrt 9\\\\~~~~~~~~~~~~=3$

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2 years ago

The probability that an event will occur is fraction 2 over 3 . Which of these best describes the likelihood of the event occurr

Zolol [24]

Likely bc it is definitely not certain, nor impossible, but it is more likely then unlikely

7 0

3 years ago

Read 2 more answers

Solve irrational equation pls

rusak2 [61]

$\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)$

$
\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\$
$
4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\$

There's one more condition I forgot about
$-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\$

Finally
$x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}$

3 0

3 years ago

Which of the following is an example of a quantitative variable?

egoroff_w [7]

Answer:

C) A person's height, recorded in inches

Step-by-step explanation:

Quantitative Variable:

A quantitative variable is a variable which can be measured and have a numeric outcome.
That is the value of variable can be expressed with numbers.
Foe example: age, length are examples of quantitative variables.

A) The color of an automobile

The color of car is not a quantitative variable as its outcome cannot be measured and expressed in value. It is a categorical variable.

B) A person's zip code

Some variables like zip codes take numerical values. But they are not considered quantitative. They are considered as a categorical variable because average of zip codes have no significance.

C) A person's height, recorded in inches

Height is a qualitative variable because it can be measured and its value is expressed in numbers.

5 0

4 years ago

Suppose that the function g is defined for all real numbers as follows

Talja [164]

Answer:

-9

Step-by-step explanation:

-(-2-1)^2

-(1-1)^2

x>2 , so g(x) = 3

3 0

3 years ago