Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
20 plus 24
Divided by 15
Which gets you to
44 over 15 or 2 wholes and 14 over 15
The answer would be 17 because 59 - 30 = 29 and 29 - 12 =17
15 = x% from 200
<span>15 = </span><span> * 200</span>
15 = 2x / ÷ 2 (both sides)
<u>x = 7.5 [percent]</u>
