Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
Answer:
Ambot nimo hahahhahahahahhahaa
Sour milk contains less lactose than the fresh milk, as the sour milk gets converted to lactic acid and bacteria which enhances the digestion process. One important reason is that proteins take more time in getting digest than other nutrients. We know that fresh milk has a large amount of lactose.
Explanation:
The lactic acid bacteria have many benefits. They improve lactose digestion in the stomach. The lactase activity of the bacteria performs the task of digesting lactose in the product once it reaches the intestine thus fuelling the process of digestion in case of sour milk.
In fresh milk, the casein protein in contact with milk forms curdles which are difficult to digest.
