Answer:
First model gets the equation: y = 2 . 2^z
Second model gets the equation: y = 4^z
Third model gets the equation: y: = 4 . 2^z
Given: ∠JNL and ∠MNK are vertical angles and m∠MNK=90°
Prove: ∠JNL is a right angle.
Statements Reasons
1. ∠JNL and ∠MNK are vertical angles. Given
2.
Vertical angle theorem
3.
Angle congruence postulate
4.
Given
5.
<u> Substitution Property of Equality</u>
Since, the measures of angle JNL and MNK are equal and the measure of angle MNK is 90 degrees. therefore, by substitution property of equality, both the angles JNL and MNK will have an equal measure.
Therefore, 
6. ∠JNL is a right angle. Definition of right angle
Answer: y = 3x-1
Step-by-step explanation: I was never the best at doing this, but here it goes...
first start with the formula Y2-Y1/X2-X1 for this problem, lets say your Y2 is -1, your Y1 is 5, your X2 is 0, and your X1 is 2, making your equation -1-5/0-2 which equals -6/-2, which can be qritten as 3. this is your slope.
now take the equation Y-Y1 = M (X-X1) m is your slope, which is 3 in this case as stated above. your X1 is2, your Y1 is 5. plug this in and you get
y-5 = 3 (x-2) which you put into slope intercept form, which is y = mx + b
your answer should be y = 3x-1
Part a)
Answer: 5*sqrt(2pi)/pi
-----------------------
Work Shown:
r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi
Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"
============================================================
Part b)
Answer: 3*sqrt(3pi)/pi
-----------------------
Work Shown:
r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi
Note: the same issue comes up as before in part a)
============================================================
Part c)
Answer: sqrt(19pi)/pi
-----------------------
Work Shown:
r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
Answer:
16
Step-by-step explanation:
(10-6)^2
4^2=16