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IRISSAK [1]
3 years ago
14

A radioactive substance decays exponentially. A scientist begins with 200 milligrams of a radioactive substance. After 16 hours,

100 mg of the substance remains. How many milligrams will remain after 29 hours?
Mathematics
1 answer:
Aleks [24]3 years ago
7 0
For this case we have the following exponential equation:
 y = A (b) ^ t
 Where,
 A: initial amount
 b: decrease rate
 t: time in hours
 We then have to rewrite the equation for this problem:
 y = 200 * (0.5) ^ ((1/16) * t)
 For t = 29 hours we have:
 y = 200 * (0.5) ^ ((1/16) * 29)
 y = 56.93943174 mg
 Answer:
 
It will remain 56.94 mg after 29 hours
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Given: ∠JNL and ∠MNK are vertical angles and  m∠MNK=90°

Prove: ∠JNL is a right angle.

   Statements                                                     Reasons

1.  ∠JNL and ∠MNK are vertical angles.             Given

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svetoff [14.1K]
Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
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Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
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Note: the same issue comes up as before in part a)

============================================================

Part c)

Answer: sqrt(19pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi
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