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Alexxx [7]
3 years ago
15

Find the integral, using techniques from this or the previous chapter. ∫xex dx.

Mathematics
1 answer:
BigorU [14]3 years ago
6 0

Answer:

xe^{x} - e^{x} +C

Step-by-step explanation:

we will solve this using integration by parts as the problem is a product of two functions which none of them are constants.

∫udv = uv -∫vdu   ..............equ 1

∫xe^{x}

u=x ,

du= 1  

dv =e^{x}

v=∫dv= e^{x}

Substituting into  equ 1

∫udv = xe^{x} - ∫e^{x}dx

<em>∫udv = xe^{x}- e^{x} + C</em>

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Help giving brainly if correct show work to get full points ​
prohojiy [21]

Answer:

Step-by-step explanation:

This is an geometric series.

Common ratio = second number÷ first number

                       = \dfrac{4096}{-1024} = -4

To get the next number, 256 should be divide by (-4)

\dfrac{256}{(-4)}= -64 \\\\\\\dfrac{-64}{-4}=16\\\\\\\dfrac{16}{-4}=-4

The three numbers are : -64 , 16 , -4

6 0
2 years ago
1. 5 less than one fourth of x is y.
horsena [70]

Answer

y = (1/4)x - 5                 or     4y - x + 20 = 0

Explanation

To get the rule required, we interpret the sentence and write it in a mathematical form.

5 less than one fourth of x is y  

one fourth of x ⇒ (1/4)x

5 less than one fourth of x is y  ⇒  (1/4)x - 5 = y

y = (1/4)x - 5

4y = x - 20

4y - x + 20 = 0

6 0
3 years ago
What equation is equal to<br> 3/8 less than a number is 11
PtichkaEL [24]

Answer:

11=x-\frac{3}{8}

5 0
3 years ago
If 3x – 10 = 17, what is the value of 6x + 20 ?
IceJOKER [234]
3x-10=17\ \ \ \ /+10\\\\3x-10+10=17+10\\\\3x=27\ \ \ \ /:3\\\\3x:3=27:3\\\\x=9\\\\\\\\6x+20=6\cdot9+20=54+20=74



3x-10=17\ \ \ /\cdot2\\\\2\cdot3x-2\cdot10=2\cdot17\\\\6x-20=34\ \ \ \ /+40\\\\6x-20+40=34+40\\\\6x+20=74
3 0
3 years ago
Read 2 more answers
How do I find the vertex and the standard form? Plz explain
xenn [34]

Answer:

Vertex form

y = -4(x + 3)^2 + 10

Standard form;

y = -4x^2-24x - 26

Step-by-step explanation:

Mathematically, we have the vertex form as

y = a(x-h)^2 + k

(h,k) represents the vertex

We have h as -3 and k as 10

y = a(x+3)^2 + 10

To get a, we substitute any of the points

Let us use (-1,-6)

-6 = a(-1+3)^2 + 10

-6-10 = 4a

4a = -16

a = -16/4

a = -4

So we have the equation as;

y = -4(x+3)^2 + 10

For the standard form;

We expand the vertex form;

y = -4(x + 3)(x + 3) + 10

y = -4(x^2 + 6x + 9) + 10

y = -4x^2 - 24x -36 + 10

y = -4x^2 -24x -26

7 0
3 years ago
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