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masya89 [10]
4 years ago
14

Write an equivalent expression for the expression (a+b)(2+y)

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
8 0

Answer: 2a+ay+2b+by


Step-by-step explanation:

(a+b)(2+y)

=(a+b)(2+y)

=(a)(2)+(a)(y)+(b)(2)+(b)(y)

=2a+ay+2b+by

=ay+by+2a+2b



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The current (I) varies directly as the voltage (V) in an electric circuit. If the current is 4 amperes when the voltage is 100 v
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\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&&  y={{ k }}x
\end{array}\\\\
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\bf \textit{l varies directly to V}\implies l=kV
\\\\\\
\textit{now, we also know that }
\begin{cases}
l=4\\
V=100
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3 years ago
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kodGreya [7K]

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3 years ago
The assembly time for a product is uniformly distributed between 6 to 10 minutes. The probability of assembling the product betw
Wewaii [24]

Answer:

The probability of assembling the product between 7 to 9 minutes is 0.50.

Step-by-step explanation:

Let <em>X</em> = assembling time for a product.

Since the random variable is defined for time interval the variable <em>X</em> is continuously distributed.

It is provided that the random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 6 minutes and <em>b</em> = 10 minutes.

The probability density function of a continuous Uniform distribution is:

f_{X}(x)=\left \{ {{\frac{1}{b-a};\ a

Compute the probability of assembling the product between 7 to 9 minutes as follows:

P(7

                      =\frac{1}{4}\times \int\limits^{9}_{7}{1}\, dx

                      =\frac{1}{4}\times [x]^{9}_{7}\\

                      =\frac{1}{4}\times (9-7)\\

                      =\frac{1}{2}\\=0.50

Thus, the probability of assembling the product between 7 to 9 minutes is 0.50.

5 0
4 years ago
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Step-by-step explanation:

3 0
2 years ago
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What is the volume of this cylinder?
devlian [24]

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6 0
3 years ago
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