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Veseljchak [2.6K]
3 years ago
15

Which of the following lines is parallel to x=8? 3y=16 x=7 x=y y=8

Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0
Parallel lines<span> are </span>lines<span> in a plane which do not meet; that is, two </span>lines in a plane that do not intersect or touch each other at any point. Therefore, from the choices listed above, the correct answer should be the second option. The line that is parallel to x=8 should be x =7. Hope this answers the question. Have a nice day.
Firdavs [7]3 years ago
7 0

Answer: x=7 is the line parallel to the given line x=8 .


Step-by-step explanation:

Parallel lines are the lines which are always same distance apart and never intersect. The given line is x=8 with intersects the x axis at x=8 and it is parallel to y axis with slope infinite or not defined. So from the given options only x=7 is the line which is equidistant(same distance between them at any point) never intersect x=8 and is parallel to y - axis. Therefore x=7 is to line which is parallel to x=8.

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Find the exact value of sin 105º.
Jet001 [13]

Answer:

sin 105 = sin (45 + 60) = sin 45 cos 60 + cos 45 sin 60, or

                                    = (1 / √2)(1 / 2)        + (1 / √2)(√3 / 2)

                                         1 + √3

                                    = -------------

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw
slavikrds [6]

Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

b. C_{0}=122

c. k=-0.00259

d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

Tm=68

\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

c. After 33 minutes of serving the coffee has cooled to 180°:

T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

8 0
4 years ago
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Sati [7]

Answer:

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8 0
3 years ago
Rewrite Log base 4 of 4 = 1
Mkey [24]

Answer:

log_{4}(4)  = 1

4 0
3 years ago
A right rectangular prism is packed with cubes of side length fraction 1 over 5 inch. If the prism is packed with 15 cubes along
Ann [662]

Given:

A right rectangular prism is packed with cubes of side length \dfrac{1}{5} inch.

Prism is packed with 15 cubes along the length, 6 cubes along the width, and 5 cubes along the height.

To find:

The volume of the prism

Solution:

Side length of each cube =\dfrac{1}{5} inch.

15 cubes along the length, so length of prism is

l=15\times \dfrac{1}{5}=3\text{ inches}

6 cubes along the width, so width of prism is

b=6\times \dfrac{1}{5}=\dfrac{6}{5}\text{ inches}

5 cubes along the height, so height of prism is

h=5\times \dfrac{1}{5}=1\text{ inch}

Now,

Volume of rectangular prism is

V=l\times b\times h

V=3\times \dfrac{6}{5}\times 1

V=\dfrac{18}{5}

V=\dfrac{3\times 5+3}{5}

V=3\dfrac{3}{5}\text{ cubic inches}

Therefore, the correct option is B.

7 0
3 years ago
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