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3 years ago

PLEASE HELP!! DUE!! The square pyramid has a volume of 225 cubic inches. What is the value of x?

Mathematics

2 answers:

Tema [17]3 years ago

4 0

Answer:

x = 15

Step-by-step explanation:

The volume (V) of a pyramid is calculated as

V = $\frac{1}{3}$ Ah ( A is the area of the base and h the height )

Here V = 225, A = x² and h = $\frac{1}{5}$ x , thus

$\frac{1}{3}$ × x² × $\frac{1}{5}$ x = 225, that is

$\frac{1}{15}$ x³ = 225 ( multiply both sides by 15 )

x³ = 3375 ( take the cube root of both sides )

x = $\sqrt[3]{3375}$ = 15

xeze [42]3 years ago

3 0

Volume of square pyramid=lwh/3=225 in³.

l=w=Xin.

h=x/5in.

x³/15=225

x=15in.

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If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586

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The answer is option D) r < 5 or r > – 1.

I'm going to graph each inequality below on a number line.

A) r > 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

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—————

B) r > 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r5~~or~~r$

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.

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C) r < 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r$

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$\large\begin{array}{cl} \mathsf{r-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

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Here's a pic....AB is the distance with A = (0,4) and B = (5, -1)

Step-by-step explanation:

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