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Alja [10]
3 years ago
5

Malia and her sister walk at a constant rate of 4 miles per hour. At this constant rate, how long should it take Malia and her s

ister to walk 3 miles?
A. 0.75
B. 1.25
C. 1.5
D. 12
Mathematics
1 answer:
natita [175]3 years ago
8 0
A is the answer as 3/4 is 0.75
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A grocery store sells Swiss cheese for $5.90 a pound. To the nearest cent, what is the cost per ounce of Swiss cheese? Round you
Debora [2.8K]

Answer:

37 cents

Step-by-step explanation:

Given that a grocery store sells Swiss cheese

Rate per pound = 5.90 dollars

1 pound =16 oz,

Hence cost of 16 ounces is given as 5.90

SO cost of one ounce of Swiss cheese =\frac{5/90}{16} =0.36875

Or 36.875 cents

Round off to nearest cent as

37 cents since after decimal digit 8 is more than 5.

Hence answer is 37 cents

8 0
3 years ago
Lauren jogs the rate at a 2 mile every 1/2 hour. what is her until rate?
Fantom [35]

I 4 mph

Step-by-step explanation: I assume you’re writing Asking about the mph it would be be 4

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2 years ago
Consider the following three points.(-5,2), (0,6), (6,4)Step 3 of 3: Determine whether the three points are collinear or not col
Anni [7]

Step 1

Collinear points are a set of three or more points that exist on the same straight line. Collinear points may exist on different planes but not on different lines.

Step 2

Graph the points; (-5,2),(0,6),(6,4)

Step 3

Conclude based on step 2

Since the points are not a straight line, we can conclude that the 3 points are not collinear.

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11 months ago
Sara was making slug slime soup for her six friends. She needed 0.06
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2 years ago
In a G.P the difference between the 1st and 5th term is 150, and the difference between the
liubo4ka [24]

Answer:

Either \displaystyle \frac{-1522}{\sqrt{41}} (approximately -238) or \displaystyle \frac{1522}{\sqrt{41}} (approximately 238.)

Step-by-step explanation:

Let a denote the first term of this geometric series, and let r denote the common ratio of this geometric series.

The first five terms of this series would be:

  • a,
  • a\cdot r,
  • a \cdot r^2,
  • a \cdot r^3,
  • a \cdot r^4.

First equation:

a\, r^4 - a = 150.

Second equation:

a\, r^3 - a\, r = 48.

Rewrite and simplify the first equation.

\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}.

Therefore, the first equation becomes:

a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150..

Similarly, rewrite and simplify the second equation:

\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}.

Therefore, the second equation becomes:

a\, r\, \left(r^2 - 1\right) = 48.

Take the quotient between these two equations:

\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}.

Simplify and solve for r:

\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}.

8\, r^2 - 25\, r + 8 = 0.

Either \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16} or \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}.

Assume that \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}.

Similarly, assume that \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = \frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}.

4 0
2 years ago
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