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Harlamova29_29 [7]
3 years ago
7

Simon used a probability simulator to roll a 12-sided number cube 100 times. His results are shown in the table below: Number on

the Cube Number of Times Rolled 1 18 2 5 3 16 4 12 5 10 6 5 7 8 8 14 9 2 10 5 11 2 12 3 Using Simon's simulation, what is the frequency of rolling a 3 on the number cube?
100/16

100/84

16/100

84/100
Mathematics
1 answer:
barxatty [35]3 years ago
7 0
The frequency for rolling a 3 would be 5 over 100
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zmey [24]

Answer:

n = 3

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XZ = 39

Step-by-step explanation:

Given

XY = 9n + 12

XZ = 15n - 6

Solving (a): n

To solve for n;

We make use of

XY = XZ

Substitute values for XY and XZ

9n + 12 = 15n - 6

9n - 15n = -12 - 6

-6n = -18

Divide through by -6

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Solving (b) XY

XY = 9n + 12

Substitute 3 for n

XY = 9 * 3 + 12

XY = 27 + 12

XY = 39

Solving (c): XZ

XZ = XY

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3 years ago
What is the value of x? enter your answer in the box x= <br>​
zlopas [31]

Answer:

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Step-by-step explanation:

i hope it helps :)

8 0
3 years ago
213 Marks
Sophie [7]

Answer:

2121.8

Step-by-step explanation:

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Time is 2 years

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= 2000 × (1+0.03)^2

= 2000 × 1.03^2

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7 0
2 years ago
A researcher wishes to​ estimate, with 9090​% ​confidence, the proportion of adults who have​ high-speed Internet access. Her es
Sunny_sXe [5.5K]

Answer:  a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : z_{\alpha/2}=1.645

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271

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3 years ago
Which of the following functions is graphed below?
sasho [114]

Answer:

2nd choice B.

Step-by-step explanation:

You can use the options A-D to help you eliminate pretty quickly without actually graphing

So first chose says you have the graph on the left when x<1 But you should see our visual actually says we want to include what happens at 1 (the filled dot) so this isn't the answer

Second choice Possible

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Fourth choice: same reason as third choice

Answer is the 2nd

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3 years ago
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