<span>r²sin²θ = 16rcosθ </span>
<span>rsin²θ = 16cosθ </span>
<span>r = 16cosθ / sin²θ </span>
<span>r = 16cotθcscθ</span>
The answer is "C", "MW".
In the given problem, the place QMW and plane RMW. These planes intersect at MW, in which intersection is either a point, line or curve that an entity or entities both possess or is in contact with but if we see in Euclidean<span> geometry, the intersection of two planes is called a “line”. </span>In the plane we can understand that the common line for both plane QMW and plane RMW is MW.
Answer:
yes
Step-by-step explanation:
ur welcome
brainliest pls
xd
Answer:
Step-by-step explanation:
hello :
f(x) = a(x - h)²-k ....vertex form when the vertex is : (h,k)
h=1 and k=0 so : f(x) = a(x-1)²
a parabola that passes through the point (2,8) : f(2)=8
a(2-1)² =8
a= 8
f(x) = 8(x-1)²= 8(x²-2x+1)
f(x) 8x²-16x+8 .....standard form
