Z-score for a variable X is calculated using
Z(x)=(x-mean)/standard deviation.
Here
x=56
mean=65
standard deviation=5
so
Z(65)=(65-56)/5=9/5=1.8
Answer:
vertex angle = 180° - 2x
Step-by-step explanation:
Since, the measure of each base angle of an isosceles triangle is represented by x.
So, by interior angle sum postulate of a triangle, we have:
x + x + vertex angle = 180°
2x + vertex angle = 180°
vertex angle = 180° - 2x
So, the vertex angle is represented by (180° - 2x).
Answer:
sin(θ) = 24/25
Step-by-step explanation:
We can easily solve this problem by applying the trigonometric identity
sin(x) ^2 + cos(x) ^2 = 1
In this case
sin(θ) ^2 + cos(θ) ^2 = 1
sin(θ) ^2 = 1 - cos(θ) ^2
sin(θ) ^2 = 1 - (7/25) ^2
sin(θ) ^2 = 1 - (49/625)
sin(θ) ^2 = 576/625
sin(θ) = √( 576/625)
sin(θ) = 24/25
The value of sine of angle Q is 1.16
<u>Explanation:</u>
Given:
ΔQRS is a right angle triangle
∠S = 90°
QS = 33
SR = 56
QR = 65
Sin(∠Q) = ?
We know:
![sin \alpha = \frac{perpendicular}{hypotenuse}](https://tex.z-dn.net/?f=sin%20%5Calpha%20%20%3D%20%5Cfrac%7Bperpendicular%7D%7Bhypotenuse%7D)
So,
![sin(Q) = \frac{QR}{RS} \\\\Sin (Q) = \frac{65}{56} \\\\sin (Q) = 1.16](https://tex.z-dn.net/?f=sin%28Q%29%20%3D%20%5Cfrac%7BQR%7D%7BRS%7D%20%5C%5C%5C%5CSin%20%28Q%29%20%20%3D%20%5Cfrac%7B65%7D%7B56%7D%20%5C%5C%5C%5Csin%20%28Q%29%20%3D%201.16)
Therefore, the value of sine of angle Q is 1.16
Answer:
A: (-5,-2)
Step-by-step explanation:
Hopefully this helps!