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dolphi86 [110]
3 years ago
8

Help please!!!!!!!!!! Thank you

Mathematics
1 answer:
andre [41]3 years ago
4 0
2b) stretching
2c) it is stretched by a factor of 2 of the parent function f(x)=x
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A track-and-field athlete releases a javelin. The height of the javelin as a function of time is shown on the graph below. Use t
Georgia [21]
Part 1:
 
 For this case we must see in the graph the axis of symmetry of the given parabola.
 We have then that the axis of symmetry is the vertical line t = 2.
 Answer:
 
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

 
Part 2:

 
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
 We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
 Then, we must observe the moment when it returns to be 20 feet above the ground.
 For this, observing the graph we see that:
 h (3) = 20 feet
 Therefore, a height of 20 feet is again reached in 3 seconds.
 Answer:
 
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
5 0
3 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
3 years ago
Read 2 more answers
Multiplies to -1120 adds to 3
TEA [102]
With these, always write out the multiples first.

Start like this:
(assume one of the factors is negative)
1 and 1120
2 and 560
4 and 280
5 and 224
7 and 160
8 and 140
10 and 112
14 and 80
16 and 70
20 and 56
28 and 40
32 and 35

from those, the obvious choice is the one with a difference of three. In this case, 32 and 35, because -32 + 35 equals 3.
6 0
3 years ago
I have the question in a screengrab. Thank you, whoever helps me.
nata0808 [166]

To simplify

\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}

we need to use the fact that

\sqrt[4]{x^4}=|x|

Why the absolute value? It's because (-x)^4=(-1)^4x^4=x^4.

We start by rewriting as

\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}

\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}

Since x\neq0, we have \dfrac xx=1, and the above reduces to

\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}

Then we pull out any 4th powers under the radical, and simplify everything we can:

\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}

\dfrac1{|2y|}\sqrt[4]{3x^2}

where y>0 allows us to write \dfrac yy=1, and this also means that |y|=y. So we end up with

\dfrac{\sqrt[4]{3x^2}}{2y}

making the last option the correct answer.

7 0
3 years ago
Kurt baked 9 batches of cookies. Each batch contained 9 cookies. How many cookies did Kurt bake?
soldi70 [24.7K]
9*9=81. So Kurt baked 81 cookies.
7 0
3 years ago
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