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4 years ago

What is 4.57125 rounded to?

1 answer:

5 0

That depends.

-- If you're rounding to the nearest ten-thousandth, it's 4.5713 .
-- If you're rounding to the nearest thousandth, it's 4.571 .
-- If you're rounding to the nearest hundredth, it's 4.57 .
-- If you're rounding to the nearest tenth, it's 4.6 .
-- If you're rounding to the nearest whole number, it's 5 .
-- If you're rounding to the nearest ten, or to any larger place, it's zero.

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Phil smith is a car salesman. last week his total sales amounted to 27,650.00, and he received 1,382.50 in commissions. what is

klemol [59]

Divide 1382.5 by 27650 and you will get 0.05
This means that his commission rate is 5%

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3 years ago

It cost Marc $29.75 a week to feed his dog .About how much does it cost him to feed his dog for 3 weeks?

Brrunno [24]

Answer:

$89.25

Step-by-step explanation:

If one week is 29.75, then you can infer that each week separately would be the same amount. With this information, you can form this equation:

y = 29.75x

X would be the number of weeks while y would be the final amount based off the number of weeks.

If you substitute x with 3, then you should get the final answer of 89.25.

Hope this helps!

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3 years ago

How many times larger is 400 than 4

sukhopar [10]

100

because 100 times 4 is 400.

5 0

3 years ago

Read 2 more answers

Let X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes. If the random vari

Gelneren [198K]

Answer:

Probability that the wait time is greater than 37 minutes is 0.3474.

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.

<u><em>Let X = waiting time for a car to pass by on a country road</em></u>

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as 35 minutes that means $\lambda = \frac{1}{35}$ .

So, X ~ Exp( $\lambda = \frac{1}{35}$ )

Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;

$F(x) = P(X \leq x) = 1 - e^{-\lambda x}$ , x > 0

Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X $\leq$ 37 min)

P(X $\leq$ 37 min) = $1 - e^{-\frac{1}{35} \times 37}$ {Using CDF}

= 1 - 0.3474 = 0.6525

So, P(X > 37 min) = 1 - 0.6525 = 0.3474

Therefore, probability that the wait time is greater than 37 minutes is 0.3474.

4 0

3 years ago

What is the probability that the second sock is black?

coldgirl [10]

I think it would be 5/8

5 0

3 years ago

Read 2 more answers