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3 years ago

A party rental company has chairs and tables for rent. The total cost to rent

Mathematics

1 answer:

dlinn [17]3 years ago

6 0

I do not have any idea and any operation did you do it wrong or something because I do not get it

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Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!!!

Mamont248 [21]

Answer:

y= -x^2+5

Step-by-step explanation:

It normally expontionally goes up, so across the x axis is down so it is negative, and is is all scales up, so the start is 5 up from the origin on the y axis, so it would be y=-x+5

Hope this helped!

7 0

2 years ago

Perform the indicated operation.<br> f(n) = 4n - 5, g(n) = n^2 - 5<br> Find: (f - g) (n)

Alex777 [14]

Hi there!

$\large\boxed{-n^2 + 4n}$

Begin by evaluating f - g:

4n - 5 - (n² - 5)

Simplify:

4n - 5 - n² + 5 = 4n - n²

Or it can be written as -n² + 4n to match the first answer choice.

3 0

2 years ago

A table has 16 glasses on it. 7of the glasses are large. The rest are small. How many glasses are small?

kirill [66]

9? Unless it’s a trick question

5 0

3 years ago

Read 2 more answers

PLS HELP ASAP<br> x^2 - 4x-1=0<br> Solve using formula

-BARSIC- [3]

X1=2-Square root 5 x2=2+ Square root 5

4 0

2 years ago

Read 2 more answers

A major metropolitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers.

Tpy6a [65]

Answer: $(0.36845,\ 0.43155)$

Step-by-step explanation:

Let p be the population proportion of readers who would like more coverage of local news.

As per given , we have

sample size :=1600

sample proportion : $\hat{p}=40\%=0.40$

The confidence interval for population proportion is given by :-

$\hat{p}\pm z^* \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

From z-table ,

For 99% confidence interval the z-value is 2.576.

Substitute all the values in the above formula , we get

The 99% confidence interval for the proportion of readers who would like more coverage of local news as

$0.40\pm(2.576) \sqrt{\dfrac{0.40(1-0.40)}{1600}}$

$0.40\pm(2.576) \sqrt{\dfrac{0.24}{1600}}$

$0.40\pm(2.576) \sqrt{0.00015}$

$0.40\pm(2.576) (0.0122474487139)$

$0.40\pm0.03155$

$(0.40-0.03155,\ 0.40+0.03155)=(0.36845,\ 0.43155)$

Hence, the 99% confidence interval for the proportion of readers who would like more coverage of local news is $(0.36845,\ 0.43155)$ .

5 0

3 years ago