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3 years ago

Plot the line for the equation on the graph. y−4=−1/ 4(x−5)

Mathematics

1 answer:

Svetlanka [38]3 years ago

5 0

The equation y−4=−1/4(x−5) is in the form of y=mx+b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

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In the figure shown, what fractional part of the circle is shaded?

charle [14.2K]

Answer:

4/15

Step-by-step explanation:

Add up the unshaded part

1/3 +2/5

Get a common denominator

1/3 *5/5 + 2/5 *3/3

5/15 + 6/15

11/15

Subtract this from 1 for the entire circle

15/15 -11/15

4/15

4/15 is shaded

3 0

3 years ago

Read 2 more answers

Sabendo que a-b=30 a/11=b/6,determine o valor do a e do b

timurjin [86]

I hope this helps you

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3 years ago

Guys hi am i correct ??

Sloan [31]

Yes, you are correct.

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2 years ago

The boundary line on the graph represents the equation

Pachacha [2.7K]

Answer:

x=2(3-y)/5

Step-by-step explanation:

5x=6-2y

x=6-2y/5

8 0

3 years ago

How do you solve this equation: -2m+3=|15+m|

Elden [556K]

Any number inside the modulus sign becomes positive. This means $|15+m|=|-(15+m)|=|-15-m|$ and so we have,

$-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right$

Solving these gives us

$-2m+3=15+m \Rightarrow m=-4$

$-2m+3=-15-m \Rightarrow = m=18$

However if we check the second solution in the original equation we obtain $-2(18)+3=|15+18| \Rightarrow -33=33$ . This is false and so $m=18$ can't be a solution.

Therefore the only solution is $m=-4$ .

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

8 0

3 years ago