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Inessa05 [86]
3 years ago
5

Plot the line for the equation on the graph. y−4=−1/ 4(x−5)

Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

The equation y−4=−1/4(x−5) is in the form of y=mx+b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

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If the point (x,-1) is on the unit circle what is the value of x
finlep [7]
A unit circle has its center at the origin and has a radius of one. It is modeled by the equation
x² + y² = 1

We are given with <span>(x,-1)</span> .
Solving for x
x² + (-1)² = 1
x = 0<span />
4 0
4 years ago
May somebody help me please
inessss [21]
Yes can u please type the problem 
8 0
3 years ago
A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points ex
Serga [27]
<h3>Answer:  127</h3>

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

  • first exam = 70
  • second exam = 80
  • third exam = 43
  • fourth exam = x+5

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

7 0
3 years ago
Solve for x.
Finger [1]

Answer:

I don't see an equation to solve

5 0
3 years ago
What is the slope of the graph of y= -5/3x + 3/4
Lesechka [4]

Answer:

slope = - \frac{5}{3}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{5}{3} x + \frac{3}{4} ← is in slope- intercept form

with slope m = - \frac{5}{3}

4 0
3 years ago
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