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alina1380 [7]
3 years ago
9

Which equation can be used to solve the problem? 10 is 50 percent of what number? StartFraction 10 divided by 1 Over 50 divided

by 1 EndFraction = StartFraction 10 Over 50 EndFraction StartFraction 100 times 2 Over 50 times 2 EndFraction = StartFraction 200 Over 100 EndFraction StartFraction 10 divided by 2 Over 50 divided by 2 EndFraction = StartFraction 5 Over 25 EndFraction StartFraction 50 divided by 5 Over 100 divided by 5 EndFraction = StartFraction 10 Over 20 EndFraction
Mathematics
2 answers:
SOVA2 [1]3 years ago
5 0

Answer:

its dddddddddddddddddddddddddddddddddddddddddddddddddd trust me

Step-by-step explanation:

IceJOKER [234]3 years ago
3 0

Answer:

D

Step-by-step explanation:

i took the test trust me

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4(t+25) = (t+50) - 4 (0.15t)
LenKa [72]

Answer:

4(t+25) = (t+50) - 4 (0.15t)

4t + 100 = t + 50 - 0.6t

4t + 100 = 50 + 0.4t

4t - 0.4t + 100 = 50 + 0.4t - 0.4t

3.6t + 100 = 50

3.6t + 100 - 100 = 50 - 100

3.6t = -50

3.6t / 3.6 = -50 / 3.6

t = - 13.9

Step-by-step explanation:

6 0
3 years ago
Beth is 2 years older than Jimmy, and in 3 years the sum of their ages will be twice as much as the sum of their ages 3 years ag
Alika [10]
Jimmy is 8
Beth is 10

8 0
3 years ago
On average Asia makes 14 out of 20 free throws Assuming the relationship is proportional, how many free throws is she likely to
dybincka [34]

Answer:

105

Step-by-step explanation:

14:20=7:10

150/10=15

7x15=105

3 0
2 years ago
Can someone help with 6
olga nikolaevna [1]

A. there are 20 boys and 30 girls.

B.

68.7 out of 100 Boys

Girls im not sure, maybe someone else can answer that sorry




Hope I'm right and this helps sorry i didn't get girls.

8 0
3 years ago
Which polygons are congruent?<br><br> Select <img src="https://tex.z-dn.net/?f=%5Cbold%7Beach%7D" id="TexFormula1" title="\bold{
gregori [183]
<h3>Answer: Everything but the lower right hand corner</h3>

==============================

Explanation:

Notice for the corners mentioned, we have the figures with corresponding angles that are the same (shown by similar arc markings) and they have congruent corresponding sides as well (aka they are the same length shown by similar tickmarks). Rotating one figure has it transform into the other.

The only time this does not happen is with the pair of figures in the bottom right hand corner. One square has side lengths of 20, the other has side lengths of 25. The two figures are not congruent due to the side mismatch.

8 0
2 years ago
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