The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
12
Step-by-step explanation:
(-15)/(-18) = 10/x cross multiply expressions
-15x = -180 since both sides are negative we can write without the sign
15x = 180 divide both sides by 15
x = 12
Answer:
1410
Step-by-step explanation:
-6 times 5 is -30
47 times -30 is -1410
The answer is B. 60 cubic inches
5 x 6 x 2 = 60
Answer:
Multiply 2.8 by 1.6 and that gives you the area of 4.48
