Answer:
-10
Step-by-step explanation:
You are asked to tell the y-value of the solution. You can find the whole solution and then report the y-value, or you can just find the y part of the solution. We choose the latter.
This is basically done by eliminating the x-variable. It can be done using the "elimination" method of solving these equations. And it can also be done using the "substitution" method of solving these equations. We choose the latter.
Add 14 to the second equation to solve for x:
... x = y + 14
Substitute this into the first equation.
... 3(y +14) -y = 22
... 2y +42 = 22 . . . . . . simplify
... y +21 = 11 . . . . . . . . divide by 2
... y = -10 . . . . . . . . . . subtract 21
_____
<em>Comment on additional solution methods</em>
A graphing calculator can show you the solution, as in the attachment. Of the solution (x, y) = (4, -10), we are only interested in y = -10.
Cramer's rule can find just one variable value, too. For that, it is convenient to write the system as ...
- 3x -y = 22
- x - y = 14 . . . . . add 14-y to the equation given
Then the solution for y is ...
... y = (22·1 -14·3)/(-1·1 -(-1)·3) = -20/2 = -10
Answer:
10x-5
Step-by-step explanation:
f(x)=5x
g(x)=2x-1
To create a composite function, replace x in f(x) with g(x)
f(g(x)) = 5(g(x) = 5(2x-1) = 10x-5
The answer is A. you basically just plug the numbers in and see which one is correct.
Answer:
y = -3x + 5
Step-by-step explanation:
To graph a linear equation in slope-intercept form, we can use the information given by that form. For example, y=-3x + 5 tells us that the slope of the line is -3 and the y-intercept is at (0,5). This gives us one point the line goes through, and the direction we should continue from that point to draw the entire line.
Cos theta = 1 /sec theta so cos theta = 1/2
and 4 cos theta = 4 * 1/2 = 2
sin theta = sqrt ( 1 - cos^2 theta) = sqrt 1 - 1/4) = sqrt (3/4) = sqrt3/2
root 3 sin theta = 3/2
tan theta = sin theta / cos theta = sqrt3 / 2 / 1/2 = 2*sqrt3/ 2 = sqrt3
so the answer is 2 - 3/2 / sqrt3 = 1/2 / sqrt3 = sqrt3 / 6