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3 years ago

3/9 + 3/27 = ? Adding fractions

1 answer:

4 0

$\frac{3}{9}$ + $\frac{3}{27}$ equals $\frac{4}{9}$ .

First, simplify $\frac{3}{9}$ to $\frac{1}{3}$ and also $\frac{3}{27}$ to $\frac{1}{9}$ . Your problem should look like: $\frac{1}{3}$ + $\frac{1}{9}$ .
Second, find the least common denominator of $\frac{1}{3}$ and $\frac{1}{9}$ to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: $\frac{1x3}{3x3}$ + $\frac{1}{9}$ .
Fourth, simplify to get the denominators the same. Your problem should look like: $\frac{3}{9}$ + $\frac{1}{9}$ .
Fifth, join the denominators. Your problem should look like: $\frac{3+1}{9}$ .
Sixth, simplify. Your problem should look like: $\frac{4}{9}$ , which is the answer.

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Whats the least common multiple of 7, 9, and 21

Marina86 [1]

Answer:

Step-by-step explanation:

8 0

3 years ago

HELP ME AND PLS AND THXS (-1, -16) (3, 0) (-5, 0) (0, -15)

n200080 [17]

Answer:

A. (-1, -16)

Step-by-step explanation:

8 0

2 years ago

Ten less than three times the sum of a number and five is equal to twenty-nine. What is the number ?

kozerog [31]

Hello!
So the following would be your equation.
3(x+5)-10= 29
Your first step would be to use the Distributive Property based upon PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction). Since we have Parenthesis, we distribute first.
3(x+5)-10=29
^ ^
——————
So, your new equation would be—
3x+15-10=29
Now, you need to combine like terms—
15-10=29
3x+5=29
——————
Therefore your new equation is—
3x+5=29.
Now you need to move the constants (5,29) to one side of the equal sign. To do this, you would use the Subtraction Property of Equality and rid the 5–
3x+5=29
-5 -5
——————
Your equation is now—
3x=24.
Finally, you need to remove the 3 from x. This means you must use the Division Property of Equality, and rid the 3.
3x=24
— —
3 3
Your solved equation is—
X=8

Hope this helped!
~KayEmQue

3 0

2 years ago

Mary used one big bag of flour. She baked four loaves of bread. Then, she used the remaining flour to make 48 muffins. How much

algol [13]

Answer:

Amount of flour in the bag when Mary began = $4x+48y$

Step-by-step explanation:

Given:

Number of baked loaves of bread made from flour = 4

Number of muffins made from flour = 48

To find: Amount of flour in the bag when Mary began

Solution:

Let x denotes amount of flour used to make one baked loave of bread and y denotes amount of flour used to make one muffin.

So,

Amount of flour used to make 4 baked loaves of bread = 4 x

Amount of flour used to make 48 muffins = 48 y

Amount of flour in the bag when Mary began = $4x+48y$

3 0

3 years ago

Please help me with these two math problems that I do not quite understand. This is urgent!

g100num [7]

Answer:

1) $a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

$a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.$

"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2) is already an Explicit Formula, since it is given the first term $a_{1}=-1$ the common difference $d=-2$ let's find some terms of this Sequence through this Explicit Formula:

$a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $(4,12,20,28, ..)$ In this Arithmetic Sequence the common difference is 8, the first term value is 4.

Then, just plug in the first term and the common difference into the explicit formula:

$a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

6 0

2 years ago