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son4ous [18]
3 years ago
11

3/9 + 3/27 = ? Adding fractions

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
\frac{3}{9} + \frac{3}{27} equals \frac{4}{9}.

First, simplify \frac{3}{9} to \frac{1}{3} and also \frac{3}{27} to \frac{1}{9}. Your problem should look like: \frac{1}{3} + \frac{1}{9}.
Second, find the least common denominator of \frac{1}{3} and \frac{1}{9} to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: \frac{1x3}{3x3} + \frac{1}{9}.
Fourth, simplify to get the denominators the same. Your problem should look like: \frac{3}{9} + \frac{1}{9}.
Fifth, join the denominators. Your problem should look like: \frac{3+1}{9}.
Sixth, simplify. Your problem should look like: \frac{4}{9}, which is the answer.

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For how many three digit numbers (100 to 999) is the sum of the digits even? (For example, 343 has an even sum of digits: 3 + 4
n200080 [17]

Answer:

there are 425 numbers of three digits whose the sum of the digits is even.

Step-by-step explanation:

Option 1:

It is necessary to accomplish one of the next conditions:

(1) all of the digits are even.

(2) exactly 2 of the digits are odd

Then, for the first condition:

4x5x5 = 100 -> this is because the first digit can not be 0.

for the second condition:

(3C1)*5*5*5-1*5*5 =3*125-25=350

where 3C1 is a combination.  The 3C1 determines which of the three digits is even, and it is necessary to subtract the numbers under 100 with the other 2 digits odd.

So, there are 450 numbers of three digits whose the sum of the digits is even.

Option 2:

there are 900 three digit number and 5*5*5 =125 has 3 odd numbers and 5*5*5+4*5*5+4*5*5=325 has 1 odd number, so there are 450 numbers of three digits whose the sum of the digitis is odd, so 900-450 whose the sum of the digits is even.

4 0
3 years ago
To find quotient of 4divided1/5,multiply 4 by
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Answer:

4÷1/5×4=80

divide 4 and 1/5 and you will get 20 then multiple by 4 and you will get 80

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Step-by-step explanation:

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Step-by-step explanation:

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