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son4ous [18]
3 years ago
11

3/9 + 3/27 = ? Adding fractions

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
\frac{3}{9} + \frac{3}{27} equals \frac{4}{9}.

First, simplify \frac{3}{9} to \frac{1}{3} and also \frac{3}{27} to \frac{1}{9}. Your problem should look like: \frac{1}{3} + \frac{1}{9}.
Second, find the least common denominator of \frac{1}{3} and \frac{1}{9} to get 9.
Third, make the denominators the same as the least common denominator (LCD). Your problem should look like: \frac{1x3}{3x3} + \frac{1}{9}.
Fourth, simplify to get the denominators the same. Your problem should look like: \frac{3}{9} + \frac{1}{9}.
Fifth, join the denominators. Your problem should look like: \frac{3+1}{9}.
Sixth, simplify. Your problem should look like: \frac{4}{9}, which is the answer.

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For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

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In this problem, we have that:

3x^{2} + kx + 3 = 0

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