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mel-nik [20]
2 years ago
12

What is 75percent of 200​

Mathematics
1 answer:
Setler79 [48]2 years ago
4 0

Answer:

150

Step-by-step explanation:

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A store manager is inspecting two large bags of nuts. In bag A, 35% of the nuts are cashews. In bag B, 40% of the nuts are cashe
MrMuchimi

Answer:

0.339

Step-by-step explanation:

3 0
2 years ago
A regular octagon is inscribed in a circle with a radius of 10 cm. What is the length of one side of the octagon?
Semenov [28]

Answer:

The length of one side of the octagon is 7.65 cm

Step-by-step explanation:

The parameters given are;

A regular octagon inscribed in a circle of radius, r, of 10 cm.

The length of each side is found from the isosceles triangle formed by the radius and one side of the octagon

The sum of interior angles in a polygon, ∑θ_i = 180 × (n - 2)

Where;

n = The number of sides of the polygon

θ_i = The interior angle of the polygon

For the octagon, we have;

n = 8, therefore;

∑θ_i = 180 × (8 - 2) = 1080

Given that there are eight equal angles in a regular octagon, we have;

∑θ_i = 8 × θ_i = 1080

θ_i = 1080/8 = 135°

The sum of angles at the center of the circle = 360

Therefore, the angle at the center (tip angle) of the isosceles triangle formed by the radius and one side of the octagon = 360/8 = 45°

The base angles of the isosceles triangle is therefore, (180 - 45)/2 = 67.5° = θ_i/2

The length of the base of the isosceles triangle formed by the radius and one side of the octagon = The length of one side of the octagon

From trigonometric ratios, the length of the base of the isosceles triangle is therefore;

2 × r × cos(θ_i/2) = 2×10 × cos(67.5°) = 7.65 cm

The length of the base of the isosceles triangle = 7.65 cm = The length of one side of the octagon.

7 0
3 years ago
Read 2 more answers
(0.7) exponent 2 please help!
ratelena [41]
The answer is 0.49
0.7 x 0.7 = 0.7^2
7 0
3 years ago
the greatest common factor of 18 and a mystery number is 6.Give three possible values for the mystery number
Rudiy27

3,2,9 because the factors of 18 are ... 6,9,2,3
5 0
3 years ago
the vertices of ABC are points A(1,1), B(4,1), and C(4,5). find the cosines of the angles of the triangle.
pickupchik [31]

Answer:

  • cos(A) = 3/5
  • cos(B) = 0
  • cos(C) = 4/5

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between the cosine of an angle and the sides of the triangle.

  Cos = Adjacent/Hypotenuse

__

<h3>Angle A</h3>

In the given triangle, the hypotenuse is AC. The side adjacent to angle A is AB, so its cosine is ...

  cos(A) = AB/AC

  cos(A) = 3/5

__

<h3>Angle B</h3>

The right angle in the triangle is angle B. The cosine of a right angle is 0.

  cos(B) = 0

__

<h3>Angle C</h3>

The side adjacent to angle C is CB, so its cosine is ...

  cos(C) = CB/AC

  cos(C) = 4/5

7 0
2 years ago
Read 2 more answers
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