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ElenaW [278]
3 years ago
5

Who knows how to solve for -3= (5e+2)

Mathematics
1 answer:
Savatey [412]3 years ago
5 0
I'm not sure but you can download an app for it to give you answers hope that helped
3 - 296 -
You might be interested in
M is between L and C. LM=11, MC=2x+5, and LC=6x-6. What is MC?
vlabodo [156]
6(2x+5)-6=0
(12x+30)-6=0
             +6 +6
12x+30=6
       -30 -30
12x=-24
/12   /12
x=-2
MC=2(-2)+5
MC=-4+5
MC=1

LM=11
MC=1
LC=-18
3 0
3 years ago
Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.3 centimeters (
oksian1 [2.3K]

Answer:

a) For this case we can use this:

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

So the range of lengths would be 32.1 and 46.5 since on the middle of these two values we have 1-0.0015-0.0015=0.997 or 99.7 % of the values.

b) P(X>36.9)

And using the complement rule we have:

P(X>36.9)= 1-P(X

Step-by-step explanation:

Previous concepts

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

Let X the random variable who represent the variable of interest.

From the problem we have the mean and the standard deviation for the random variable X. E(X)=39.3, Sd(X)=2.4

So we can assume \mu=39.3 , \sigma=2.4

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

So we have the following probabilities using this rule:

P(X    

P(X>\mu +\sigma)=P(X >41.7)=0.16  

P(X    

P(X>\mu +2*\sigma)P(X>44.1)=0.025

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

Part a

For this case we can use this:

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

So the range of lengths would be 32.1 and 46.5 since on the middle of these two values we have 1-0.0015-0.0015=0.997 or 99.7 % of the values.

Part b

For this casee we want this probability:

P(X>36.9)

And using the complement rule we have:

P(X>36.9)= 1-P(X

5 0
3 years ago
Please help meeee!!!!!!!!!1
andrew11 [14]

D) its hard to keep something a secret, seems like the most accurate answer for this question.

5 0
3 years ago
Read 2 more answers
I tried to answer this but not getting the right answer. Can someone help me plzzz
katovenus [111]

Answer: 17

Step-by-step explanation:

Use the Pythagorean theorem.

C^2 = A^2 + B^2

So, C is always the hypotenuse which is the longest side length and the side length diagonal of the right angle. Side "s" is the hypotenuse.

Square sides AB and BD

It looks like this:

C^2 = 8^2 + 15^2

8^2 = 64

15^2 = 225

225 + 64 = 289

the square root of 289 is 17

17 = s

8 0
3 years ago
Organizing a data set allows you to do each of the following except:
kicyunya [14]

Answer:

B. take up less space than when the data set is not organized

Step-by-step explanation:

Well, in this question, you can analyze one answer after the other.

In A see important values in the data set, this makes sense when determining mode and median of a data set.Median is the center value in a data set, while mode is the repeated value in the set.When data set is arranged from smallest to the largest, the median and mode can be seen clearly.These can be the important values in the data set

In C. More easily see the maximum and minimum values in the data set, is possible especially when data is arranged in an increasing order.The smallest value will start, where as the largest value will be at the end.This applies to D too.

However in B, it will depend with the manner you would like to analyze the data.For example organizing data using tables will make your data easy to understand and present your analysis.Another person will group the data in intervals to identify the frequency of in data set.So, you see, its not about space taken by data but how you would like to present your data when analyzing it.

Hope this helps.

7 0
3 years ago
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