The correct classification for the polygon would be a concave hexagon.
Subtract 4 from both sides
y−4≤−2x
Divide both sides by −2
- y-4/2 ≥ x
Switch sides
<span>x ≤ − y−4/2<span><span><span><span><span></span></span></span>
HOPE THIS HELPS!!
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Answer:
The coordinates are (2,8)
Step-by-step explanation:
A hole is where both the numerator and the denominator are zero
f(x)=x^2+4x−12 / x−2
Factor the numerator
f(x) = (x+6) (x-2)/ (x-2)
The hole will occur where x-2 =0
x-2=0
Add 2 to each side
x-2+2 =0+2
x=2
There is a hole at x=2
If we could cancel the x-2 values from the top and bottom, we are left with
f(x) = x+6
At x=2
f(2) = 6+2
f(2) would be 8
The coordinates are (2,8)
There is a hole
Remark
You can get it just by looking at the net. It has 6 squares. Each square has a side of 5 cm by 5cm. Find the area of 1 square and multiply by 6.
Step One
Find the area of one square.
<u>Formula</u>
Area = s^2
<u>Solve</u>
Area for 1 square = s^2 = 5^2 = 25 cm^2
Step Two
Find the area for six squares.
Area of the net = 6*Area of one square = 6 * s^2
6*s^2 = 6 * 25
Area = 150 cm^2
The answer should be X^15X^6 but that doesn’t seem to be an option.
The photo is attached.
