All you need to do is divide -1/2 onto the other side.
-1/2x<-12
-12/ (-1/2)= 6 (a negative and a negative equals a positive)
Also, since you are dividing a negative, you flip the sign.
x>6
I hope this helps!
~cupcake
Answer and Step-by-step explanation:
Yes, the three side lengths could form a triangle.
To find out if the sides can form a triangle, you take the lowest side lengths and add them together. If they are <u>greater </u>than the longest side, then they can form a triangle. <u>If it is equal or less than the longest side,</u> then it CAN NOT form a triangle.
7.8 + 10.4 > 13
18.2 > 13
<u>So, the answer is Yes.</u>
<u><em>#teamtrees #PAW (Plant And Water)</em></u>
Angles in a triangle add up to 180 degrees.
All angles in an equilateral triangle have equal values
Both angle x and y equal 60 degrees.
Answer:
Piper's claim is not correct.
Step-by-step explanation:
3(2(-3)+2) = 5(-3)+6
3(-6+2) = -15 + 16
-18 + 6 = 1
-12 = 1
Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
