Answer:
The man wins 9 times and looses 11 times in the rock - paper-scissor game.
Step-by-step explanation:
Let us assume that in the game:
Number of times man wins the games = x times
Number of times man loses the games = y times
Total number of attempts = 20
Points after winning = 5
Points after loosing = 2
Now, according to the question:
x + y =20
and 5 x + 2 y = 67
Now, from (1) y = 20-x, put in (2)
5x + 2y = 67 ⇒ 5x + 2(20 -x) = 67
or, 5x -2x = 67 - 40
or, 3x = 27
⇒ x = 27/3 = 9
then y = 20 - x = 20 - 9 = 11
⇒ x = 9 and y = 11 is the solution of the given system.
Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.
