Answer:
I'm not so sure about this one so sorry if this is wrong
Step-by-step explanation:
![\bf \qquad \textit{Simple Interest Earned}\\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$690.65\\ r=rate\to 7.3\%\to \frac{7.3}{100}\to &0.073\\ t=years\to &\frac{15+31+30+6}{365} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%7D%5C%5C%5C%5C%0AI%20%3D%20Prt%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AI%3D%5Ctextit%7Binterest%20earned%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%24690.65%5C%5C%0Ar%3Drate%5Cto%207.3%5C%25%5Cto%20%5Cfrac%7B7.3%7D%7B100%7D%5Cto%20%260.073%5C%5C%0At%3Dyears%5Cto%20%26%5Cfrac%7B15%2B31%2B30%2B6%7D%7B365%7D%0A%5Cend%7Bcases%7D)
the penalty he'll incurred into, since July 6 is after the deadline of April 15, is I = Prt
now "t" is in years, how many days after April 15 to July 6? well, 15 + 31 + 30 +6, to convert to years, divide by 365
Convex Polygons

All of its angles are less than 180°.
All of the diagonals are internal.
Concave Polygons

At least one angle measures more than 180°.
At least one of the diagonals is outside the shape of the polygon.
Equilateral Polygons

All sides are equal.
Equiangular Polygons

All angles are equal.
Regular Polygons

They have equal angles and sides
Irregular Polygons
They do not have equal angles and sides.
Types of Polygons based on Number of Sides
Triangle

3 sides.
Quadrilateral

4 sides.
Pentagon

5 sides.
Hexagon

6 sides.
Heptagon

7 sides.
Octagon

8 sides.
Enneagon or Nonagon

9 sides.
Decagon

10 sides.
Hendecagon

11 sides.
Dodecagon

12 sides.
Tridecagon or triskaidecagon

13 sides.
Tetradecagon or tetrakaidecago

14 sides.
Pendedecagon

15 sides.
Hexdecagon

16 sides.
Heptdecagon

17 sides.
Octdecagon

18 sides.
Enneadecagon

19 sides.
Icosagon

20 sides.
Answer:
35/37
Step-by-step explanation:
Answer:
<em>i</em>
Step-by-step explanation:
The square root of a negative number is identified as an imaginary number (<em>i </em>)
An imaginary number (i) with exponent 3 or any other exponent remains an imaginary number.
The answer is:
<em>i</em>