All categories

3 years ago

I need help i don’t get it

Mathematics

2 answers:

Anastaziya [24]3 years ago

8 0

The answer is 4337 ÷ 9

Dmitry [639]3 years ago

7 0

The correct answer is 4,337 ÷ 9. When I did the long division out for that one, I got a remainder of 8, which is greater than seven. I would show my work, but I don't know how to. I hope this helps though.

You might be interested in

I need help with this question.

Alborosie

Answer:

2116

Step-by-step explanation:

hope this helps :)

5 0

3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

4 years ago

Samuel used 1/5 an ounce of butter to make 1/25 of a pound of jelly. How many ounces of butter is there per pound of jelly?

ikadub [295]

There will be 5ounces of peanut butter for every pound of jelly

6 0

3 years ago

Read 2 more answers

The average distance between the Earth and the Moon is 384 400 km.<br> Express it in standard form.

ycow [4]

Answer:

$3.84\times10^8\ m$

Step-by-step explanation:

It is given that,

The average distance between the Earth and the Moon is 384 400 km.

We need to express in in standard form.

1 km = 1000 m

It means,

384400 km = 384400000 km

= $3.84\times10^8\ m$

Hence, the average distance between the Earth and the Moon is $3.84\times10^8\ m$ .

3 0

3 years ago

___________________

strojnjashka [21]

Answer:

The answer is A

Step-by-step explanation:

6 0

3 years ago