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cupoosta [38]
3 years ago
6

Can u help me on this one?

Mathematics
1 answer:
maxonik [38]3 years ago
3 0

9 x 60 is 540 seconds

and 9 / 60 = .15 hours

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Find what a equals in this equation.<br><br> <img src="https://tex.z-dn.net/?f=x%28x%2Ba%29%28x%2B3%29%20%3D%20x%28x%2B3%29%28x-
galina1969 [7]

Answer:

a = - 3

Step-by-step explanation:

The equation has common factors x(x + 3) on both sides

For the 2 sides of the equation to be equal, then the factor

(x + a) = (x - 3) and by comparison

a = - 3

4 0
3 years ago
Solve 2x^2 − 8x = −7
kenny6666 [7]

Answer:

The answer to your question is below

Step-by-step explanation:

                                2x²  -   8x   =  - 7

Divide by 2

\frac{2}{2} x^{2}  - \frac{8}{2} x    = \frac{-7}{2}

Complete the trinomial

x^{2}  - 4x + (2)^{2}  = \frac{-7}{2} + (2)^{2}

Simplify

x^{2}  - 4x  + (2)^{2}  = \frac{- 7 + 4}{2}

x^{2}  - 4x + 4 = \frac{-3}{2}

Factor

(x - 2)²  =  \frac{-3}{2}

Get the square root

\sqrt{(x - 2)^{2}} = \sqrt{\frac{-3}{2}}

Simplification

               x - 2 =± \sqrt{\frac{3}{2}} i

      x₁ = 2 + \sqrt{\frac{3}{2}} i

       x₂ = 2 - \sqrt{\frac{3}{2}}

6 0
3 years ago
What is the value of the function at x = 2
notsponge [240]
2 because X=2 i think . is there any more information you could give me.

7 0
3 years ago
Given that there were 4 Heads in the first 7 tosses, find the probability that the 2nd Heads occurred at the 4th toss. Give a nu
tamaranim1 [39]

Answer:

The probability that the 2nd Heads occurred at the 4th toss is 5.99%.

Step-by-step explanation:

Given that there were 4 Heads in the first 7 tosses, to find the probability that the 2nd Heads occurred at the 4th toss the following calculation must be performed:

7 - 4 = 3

4/7 x 3/7 x 3/7 x 4/7 = X

0.571 x 0.428 x 0.428 x 0.571 = X

0.0599 = X

Therefore, the probability that the 2nd Heads occurred at the 4th toss is 5.99%.

6 0
3 years ago
Solve for k. NO LINKS OR FILES WILL GIVE BRAINLEST!!!
nataly862011 [7]
Answer is 176

k=16*11
k= 176
6 0
3 years ago
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