Answer:
D it
Step-by-step explanation:
We have two equations, A quadratic and a linear equation.
The domain of a linear equation and quadratic equation is all real numbers but since it dealing with time we must make sure the roots or x-intercepts is positive.
Looking at the quadratic equation, we can use the discramnt formula to see if all roots are positve.



The discramnt is greater than zero so there is two distinct real roots. So let check if they are positve
If you graph the equation, it intercepts at two positve roots so it is D
FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE. For this case what we have is the following:
For the two semicircles we can model it as a complete circle.
We have to then:
Perimeter:
P = 2 * pi * r
or
P = pi * d
Where,
r = radius
d = diameter
Therefore the perimeter is:
P = 10 * pi
For the largest circle we have:
radius = 10
Perimeter:
P '= 2pi10
P '= 20pi
1/4 since 1/4 circle:
P '' = 20pi / 4 = 5pi
Then, the total perimeter of the source is:
Pt = P + P '' = 10pi + 5pi = 15pi
Pt = 15 * (3.141592)
Pt = 47.1239
round
Pt = 47.1 ft
Area:
The total area will be:
A = A (two semicircles) + A (quarter big circle)
A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
A = 98.17477042 feet ^ 2
Round:
A = 98.2 feet ^ 2
Answer:
Perimeter of the source:
Pt = 47.1 ft
Area of the source:
A = 98.2 feet ^ 2
Answer:
B. n-3
Step-by-step explanation:
If x is an even integer, the next consecutive even integer = x + 2
Since (n-5) is even, the next consecutive even integer = (n-5) + 2 = n-3
Answer:
3600
Step-by-step explanation:
the formula to find the area of a square is:
A=a2
the formula to find the perimeter of a square is:
P=4a
hope that helps
Answer:

Step-by-step explanation:
Surface area of cylinder = 2πr(h + r)
Volume of cylinder = πr²h
Given that S.A = Volume of the cylinder, therefore, we have:
2πr(h + r) = πr²h
Radius (r) is given as 2.5 cm
height (h) = x cm
Input the values and solve for x
2πr(h + r) = πr²h
2πr(h + r) = πr(rh)
2(h + r) = rh (πr cancels πr)


Subtract 2x from both sides


Divide both sides by 0.5


