2y + 2x = 6
2y - x = 12
Subtract
3x = -6, x = -2
2(-2) + 2y = 6
-4 + 2y = 6
2y = 10, y = 5
Final solution: x = -2, y = 5
Which one the highlight one
They both have to be above the x axis, which makes B incorrect. B will be below the x axis. If you have a graphing calculator or know where there is one of the net, you can try it.
A and D are both wrong. The 1/2 does not become 2. What will happen is that 2 will make the graph wider.
There's only 1 answer left and that is
C <<<<<===== answer.
C reflects right across the y axis.
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Probablity=desiredoutcomes/totalpossibleoutcomes
total possible outcomes=1+2+4+3=10
desired outcomes=4 blue
probablity=4/10=2/5=40%
