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konstantin123 [22]
3 years ago
8

Implement the function couple, which takes in two lists and returns a list that contains lists with i-th elements of two sequenc

es coupled together. You can assume the lengths of two sequences are the same. Try using a list comprehension.
Computers and Technology
1 answer:
In-s [12.5K]3 years ago
7 0

Answer:

couple.py

def couple(s1,s2):

  newlist = []

  for i in range(len(s1)):

      newlist.append([s1[i],s2[i]])

  return newlist

s1=[1,2,3]

s2=[4,5,6]

print(couple(s1,s2))

enum.py

def couple(s1,s2):

  newlist = []

  for i in range(len(s1)):

      newlist.append([s1[i],s2[i]])

  return newlist

def enumerate(s,start=0):

  number_Array=[ i for i in range(start,start+len(s))]

  return couple(number_Array,s)

s=[6,1,'a']

print(enumerate(s))

print(enumerate('five',5))

Explanation:

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<u>C program for finding size of different data types</u>

#include <stdio.h>

//driver function

int main()

{

   int a;  //declaring a of type int

   float b; //declaring b of type float

   double c; //declaring c of type double

   char d; //declaring d of type char

   long e; //declaring e of type long

   long long f; //declaring f of type longlong

   unsigned g; //declaring g of type unsigned

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printf("unsigned data type contains: %lu byte\n",sizeof(g)); /*Finding size of unsigned */

   return 0;

}

<u>Output</u>

int data type contains: 4 bytes

float data type contains : 4 bytes

double data type contains: 8 bytes

char data type contains: 1 byte

long data type contains: 8 byte

longlong data type contains: 8 byte

unsigned data type contains: 4 byte

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