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Vladimir79 [104]
3 years ago
14

Thanks for the help

Mathematics
2 answers:
Murljashka [212]3 years ago
6 0

[(3+5)x2-5] x 3

Do the parentheses first.

[8 x 2 - 5] x 3

Then multiplication.

[16 - 5] x 3.

Now the brackets.

[11] x 3 = 33

If this helped you, please list me as brainliest!

Whitepunk [10]3 years ago
4 0

[(3 + 5) x 2 - 5] x 3

= [8 x 2 - 5] x 3

= [16 - 5] x 3

= 11 x 3

= 33

Answer

33

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Find the possible dimensions of the picture above please
Svetlanka [38]

Answer:

(2x – 7) × (2x + 7)

Step-by-step explanation:

From the question given above, the following data were obtained:

Area (A) = (4x² – 49) m²

Dimension =?

The picture in the question above has a rectangular shape. Thus, the area is given by:

Area (A) = Length (L) × Width (W)

A = L × W

The dimension of the shape will be:

L × W

Now, we shall determine the dimension (L × W) as follow:

Area (A) = (4x² – 49) m²

Dimension (L × W) =?

A = L × W

L × W = 4x² – 49

Recall:

4 = 2²

49 = 7²

Thus,

L × W = 2²x² – 7²

L × W = (2x)² – 7²

Different of two squares

L × W = (2x – 7)(2x + 7)

L × W = (2x – 7) × (2x + 7)

Dimension = (2x – 7) × (2x + 7)

Therefore, the possible dimension (L × W) of the shape is (2x – 7) × (2x + 7)

4 0
3 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
Where should a fourth point be located to form a square?
Rina8888 [55]

The answer is (3,-4) because it machtes up with (-5,-4) and (3,4), so it (3,-4) is correct.

 

3 0
3 years ago
Read 2 more answers
find the mean of the data set. if necessary, round to the nearest tenth. 15.8, 14.9, 16.7, 17.6, 13.4 15 points
lana [24]
I believe that answer is 15.7.
6 0
3 years ago
The sum of the digits of a two-digit nunber is 7. When you reverse the digits of the original number the new number is 27 more t
anzhelika [568]

Answer:

25

Step-by-step explanation:

2+5=7

25 reversed is 52

52-25=27

8 0
3 years ago
Read 2 more answers
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